X^2+4x-122=0

Solution for X^2+4x-122=0 equation:

X^2+4X-122=0

a = 1; b = 4; c = -122;
Δ = b2-4ac
Δ = 42-4·1·(-122)
Δ = 504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{504}=\sqrt{36*14}=\sqrt{36}*\sqrt{14}=6\sqrt{14}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-6\sqrt{14}}{2*1}=\frac{-4-6\sqrt{14}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+6\sqrt{14}}{2*1}=\frac{-4+6\sqrt{14}}{2}
$